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Home/ Questions/Q 925625
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T19:33:02+00:00 2026-05-15T19:33:02+00:00

I have code that looks like this: extern C __declspec(dllexport) myInterface(int id, void** pFunction)

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I have code that looks like this:

extern "C" __declspec(dllexport)  myInterface(int id, void** pFunction)
{
   ...
}

I need to make the void** pFunction argument point to a function so that the caller can use this function via the pFunction pointer. This function gets called through a DLL, I don’t want to do it this way but for a lot of reasons I have no choice. I know that COM is made for this but I can not use it, the reasons come down to management.

At this point I have no idea how to do this, everything I have tried to do gives me cast problems. Do anyone have any idea how I can do this? I can post more if this is unclear.

Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T19:33:03+00:00Added an answer on May 15, 2026 at 7:33 pm

    As Jonathan Leffler and David Thornley mentioned, you aren’t guaranteed that a function pointer can be converted to void* and back. A portable workaround would be to package the function pointer into a struct and to pass a pointer to that.

    (Be aware that void** itself might have its own issues. You can avoid this too.)

    For example:

    typedef int (*SomeFuncType)(int);
    
    struct FuncWrapper
    {
        SomeFuncType func;
        void* output;
    };
    
    ...
    FuncWrapper funcWrapper;
    funcWrapper.func = ...;
    
    myInterface(id, &funcWrapper);
    

    and then myInterface could be implemented as:

    void myInterface(int id, FuncWrapper* funcWrapper)
    {
        funcWrapper->func(...);
        funcWrapper->output = ...;
    }
    
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