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Home/ Questions/Q 9145407
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T10:30:24+00:00 2026-06-17T10:30:24+00:00

I have code that stores matrices of different types, e.g. m1: Array[Array[Double]], m2: List[List[Int]]

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I have code that stores matrices of different types, e.g. m1: Array[Array[Double]], m2: List[List[Int]]. As seen, these matrices are all stored as as a sequence of rows. Any row is easy to retrieve but columns seem to me to require traversal of the matrix. I’d like to write a very generic function that returns a column from a matrix of either of these types. I’ve written this in many ways, the latest of which is:

/* Get a column of any matrix stored in rows */

private def column(M: Seq[Seq[Any]], n: Int, c: Seq[Any] = List(),
                     i: Int = 0): List[Any] = {
    if (i != M.size) column(M, n, c :+ M(i)(n), i+1) else c.toList

This compiles however it doesn’t work: I get a type mismatch when I try to pass in an Array[Array[Double]]. I’ve tried to write this with some view bounds as well i.e.

private def column[T1 <% Seq[Any], T2 <% Seq[T1]] ...

But this wasn’t fruitful either. How come the first code segment I wrote doesn’t work? What is the best way to do this?

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  1. Editorial Team
    Editorial Team
    2026-06-17T10:30:25+00:00Added an answer on June 17, 2026 at 10:30 am

    If you don’t care about the return type, this is a really simple way to do it:

      def column[A, M[_]](matrix: M[M[A]], colIdx: Int)
        (implicit v1: M[M[A]] => Seq[M[A]], v2: M[A] => Seq[A]): Seq[A] =
        matrix.map(_(colIdx))
    
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