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Home/ Questions/Q 6730831
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T10:27:22+00:00 2026-05-26T10:27:22+00:00

I have code, where ZipInputSream is converted to byte[], but I don’t know how

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I have code, where ZipInputSream is converted to byte[], but I don’t know how I can convert that to inputstream.

private void convertStream(String encoding, ZipInputStream in) throws IOException,
        UnsupportedEncodingException
{
    final int BUFFER = 1;
    @SuppressWarnings("unused")
    int count = 0;
    byte data[] = new byte[BUFFER];
    while ((count = in.read(data, 0, BUFFER)) != -1) 
    {
       // How can I convert data to InputStream  here ?                    
    }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T10:27:23+00:00Added an answer on May 26, 2026 at 10:27 am

    Here is how I solved this problem. Now I can get single files from ZipInputStream to memory as InputStream.

    private InputStream convertZipInputStreamToInputStream(ZipInputStream in, ZipEntry entry, String encoding) throws IOException
    {
        final int BUFFER = 2048;
        int count = 0;
        byte data[] = new byte[BUFFER];
        ByteArrayOutputStream out = new ByteArrayOutputStream();
        while ((count = in.read(data, 0, BUFFER)) != -1) {
            out.write(data);
        }       
        InputStream is = new ByteArrayInputStream(out.toByteArray());
        return is;
    }
    
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