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Home/ Questions/Q 6596061
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T18:01:28+00:00 2026-05-25T18:01:28+00:00

I have come across a situation where my program hangs, looks like deadlock. But

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I have come across a situation where my program hangs, looks like deadlock. But I tried figuring it out with jconsole and visualvm, but they didn’t detect any deadlock. Sample code:

public class StaticInitializer {

private static int state = 10;

static {
    Thread t1 = new Thread(new Runnable() {
        @Override
        public void run() {
            state = 11;
            System.out.println("Exit Thread");
        }
    });

    t1.start();

    try {
        t1.join();
    } catch (InterruptedException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    System.out.println("exiting static block");
}

public static void main(String...strings) {
    System.out.println(state);
}
}

When I execute this in debug mode then I could see control reaching
@Override
public void run() {
state = 11;

but as soon as state=11 is executed it just hangs/deadlocks. I looked in different postings in stackoverflow and I thought that static initializers are thread-safe but in that case jconsole should report this. About main thread, jconsole saying that it is in waiting state, and that’s fine. But for the thread created in static initializer block, jconsole says that it is in RUNNABLE state and not blocked. I am confused and here lacking some concept. Please help me out.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T18:01:29+00:00Added an answer on May 25, 2026 at 6:01 pm

    You’re not just starting another thread – you’re joining on it. That new thread has to wait for StaticInitializer to be fully initialized before it can proceed, because it’s trying to set the state field… and initialization is already in progress, so it waits. However, it’s going to be waiting forever, because that initialization is waiting for that new thread to terminate. Classic deadlock.

    See the Java Language Specification section 12.4.2 for details about what’s involved in class initialization. Importantly, the initializing thread will “own” the monitor for StaticInitializer.class, but the new thread will be waiting to acquire that monitor.

    In other words, your code is a bit like this non-initializer code (exception handling elided).

    final Object foo = new Object();
    synchronized (foo)
    {
        Thread t1 = new Thread(new Runnable() {
            @Override
            public void run() {
                synchronized (foo) {
                    System.out.println("In the new thread!");
                }
            });
        t1.start();
        t1.join();
    });
    

    If you can understand why that code would deadlock, it’s basically the same for your code.

    The moral is not to do much work in static initializers.

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