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Home/ Questions/Q 9190501
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T20:28:35+00:00 2026-06-17T20:28:35+00:00

I have come across some code along the lines of below: if(instance != (Class*)(0))

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I have come across some code along the lines of below:

if(instance != (Class*)(0))

Could someone describe what this is doing?

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  1. Editorial Team
    Editorial Team
    2026-06-17T20:28:37+00:00Added an answer on June 17, 2026 at 8:28 pm

    It short: it tests if pointer is null or not.

    In detail: The expression (Class*)(0) is actually performing a typecast from 0 (i.e. NULL) to a pointer of type Class, it then compares this pointer (which is a constant NULL) to the pointer variable instance.

    An example:

    void Check(YourClass *instance)
    {
       if(instance != (YourClass*)(0))
          // do this
    }
    

    Now the imporatant question is why. Why not simply as:

     if(instance != 0)
          // do this
    

    Well, it is just for code-portability. Some compilers may raise warning that Class* is being compared with int (since NULL is nothing but 0, which is int). Many static-analysis tool may also complain for simple NULL check with a class-type pointer.

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