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Home/ Questions/Q 8651589
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Editorial Team
  • 0
Editorial Team
Asked: June 12, 20262026-06-12T14:06:32+00:00 2026-06-12T14:06:32+00:00

I have come up with some code and it does not compile. Error 1

  • 0

I have come up with some code and it does not compile.

Error 1 error C2296: ‘^’ : illegal, left operand has type ‘double’
2 IntelliSense: expression must have integral or enum type

The code I was able to come up with is as follows:

#include<iostream>
#include<cmath>
using namespace std;

void getnumbers();
void showmean();
void showdev();

double x1, x2, x3, mean, dev;

void getnumbers()
{
    cout<<"Please enter three numbers\n";
    cin>>x1,x2,x3;
}

void showmean()
{
    mean=(x1+x2+x3)/3;

    cout<<"The mean of"<<x1<<", "<<x2<<", "<<x3<<" is "<<mean<<endl;
}

void showdev()
{
    dev=sqrt((x1 - mean)^2) + (x2 - mean)^2 + (x3 - mean)^2/3;

    cout<<"The standard deviation of"<<x1<<", "<<x2<<", "<<x3<<" is "<<dev<<endl;
}

int main()
{
    getnumbers();
    showmean();
    showdev();

    system("pause");

    return 0;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T14:06:33+00:00Added an answer on June 12, 2026 at 2:06 pm
    1. You can’t take powers like that in C++

      • Use std::pow() or x*x for mathematical x2
    2. For multiple inputs it’s cin >> x1 >> x2 ...etc

    3. In your SD equation, your close paren is in the wrong spot I think, mathematically.

      • it should be SD = sqrt( (x*x + y*y) / z ). Your close paren makes it x + y*y/3 (or y2/3, forget precedence)
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