Question

i have converted the word file in to html file, but there is a problem, the MS-word automatically adds some style to the pages.

for example

<div align="center"></div>
<p style=""></p>
<table cellpadding="0">

<tr><img src="...."></img></tr>

</table>

i want to output to be as

 <div></div>
<p></p>
<table>

<tr><img src="...."></img></tr>

</table>

i dont want the img inline styles to be removed.

thanks in advance

update:  if it is very hard to keep img style in the file. please give me the code excluding that part. it is very urgent for me and i cant edit 1000 pages manually 

Answer 1

If you want to remove styles for a known list of tags, I don’t think its necessary to use a full weight HTML parser. Something like

expr = r'((?<=<div)|(?<=<p))[ ]+.*?>'
html_text = re.sub(expr,'>',html_text)

works just fine. Of course, you would use an array of tags you want to replace to generate the (?<=

If you have a list of style tags that you want to remove, it’s even easier. Just generate an expression like

expr = r' (style|align|myStyleTag)=".*?"'

with re.sub.

If you need a dynamic combination thereof, use a parser.

Edited in response to comments by OP:

Unfortunately, lookbehind needs fixed-size expressions, so <.* or similar won’t work. If you don’t have a fixed tag list, it’s probably better to use a preexisting framework.

An ugly way around this would be something like:

expr = "("
for i in range(1,8): ## or whatever the max/min tag lengths are
    expr += "(?<=<[a-zA-Z]{" + str(i) + "})|"
expr = expr[:-1] + ")[ ]+.*?>"

But that’s pretty bad style.