Question

I have (copied from the debugger after they were set, to make sure that’s what is actually passed to the command):

process.StartInfo.FileName = "C:\\Program Files\\Microsoft SDKs\\Windows\\v7.1\\Bin\\signtool.exe"

process.StartInfo.Arguments = " sign /f \"C:\\Users\\...\\myPfx.pfx\" /p \"myPassword\" \"C:\\Users\\...\\Desktop\\app.exe\""

but when I Start() it it doesn’t sign the app. (When I copy signtool to that folder and do it manually – it works.)
So, for debugging, I tried:

System.Diagnostics.Process.Start(@"cmd.exe", @" /k " + "\"" + process.StartInfo.FileName + "\"" + " " + "\"" + process.StartInfo.Arguments + "\"");

But I get:

‘C:\Program’ is not recognized as an internal or external command,
operable program or batch file.

So how do I get the signing to work (or at least the cmd, so I’ll be able to see what exactly is the problem)?

EDIT: Thanks everyone. The problem was as answered below – missing quotes. And though I did actually try that before posting the question (-adding quotes to everything) – it didn’t work then. It turns out I was adding some white space between the quotes and the actual parameters. So it seems that that causes an error.

Answer 1

Your filename needs to be quoted

process.StartInfo.FileName = "\"C:\\Program Files\\Microsoft SDKs\\Windows\\v7.1\\Bin\\signtool.exe\""

EDIT

Try using this instead, which works for me with dummy files

string filename = "\"C:\\Program Files\\Microsoft SDKs\\Windows\\v7.1\\Bin\\signtool.exe\""
string arguments = "sign /f \"C:\\Users\\...\\myPfx.pfx\" /p \"myPassword\" \"C:\\Users\\...\\Desktop\\app.exe\""
Process.Start("cmd.exe /k " + filename + " " + arguments)