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Home/ Questions/Q 8700521
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T02:11:09+00:00 2026-06-13T02:11:09+00:00

I have copied Jquery code from another website and Link one is working fine.

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I have copied Jquery code from another website and “Link one” is working fine. When I press on it, a popup div appear and when I click outside of the div it’s gone (which is fine). But “Link Two and Three popup divs” are not appear/disappear properly. Can you please enhance code? Please check out below link (what I have done so far)

http://jsfiddle.net/awaises/SNCtu/

Also please make sure, at a time only one div appear even I press “Link Two” or “Link Three”

Really appreciate your help!

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  1. Editorial Team
    Editorial Team
    2026-06-13T02:11:10+00:00Added an answer on June 13, 2026 at 2:11 am

    Try this much shorter demo http://jsfiddle.net/vERmV/

    Rest hope it fits the cause :)

    code

    $(function() {
        $('#hidden1,#hidden2,#hidden3').hide().click(function(e) {
            e.stopPropagation();
        });
        $(".cart-buttom1,.cart-buttom2,.cart-buttom3").click(function(e) {
    
            var id = $(this).attr('class').replace(/cart-buttom/, '');
    
            $('.popup').hide()
            $('#hidden' + id).animate({
                opacity: "toggle"
            });
    
            e.stopPropagation();
        });
    
        $(document).click(function() {
            $('#hidden1,#hidden2,#hidden3').fadeOut();
        });
    });​
    
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