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Home/ Questions/Q 426431
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T19:28:43+00:00 2026-05-12T19:28:43+00:00

I have couple questions regarding some C++ rules. Why am I able to call

  • 0

I have couple questions regarding some C++ rules.

  1. Why am I able to call a function/method from outside the class in the namespace when I include the return type? (look at the namespace test2::testclass2 in the code below) i.e. this works:

    bool b = testclass1::foo<int>(2);
    

    whereas this doesn’t: – (it doesn’t even compile – compiler throws that this is function redeclaration)

    testclass1::foo<int>(2);
    

    C++ complains that it is a function redeclaration. Is that so?

  2. This line:

    bool b = testclass1::foo<int>(2);
    

    gets called first before anything else. Is this because static methods get created always first before anything else in C++?

  3. Where can I find those rules? I have a few C++ books at home, so if someone would be kind enough to either point out a book (and chapter or page) or direct me to a website I would greatly appreciate it.

Here below is the sample (partial) code that I tested at home with Visual Studio 2008:

class testclass1
    {
    public:
        testclass1(void);
        ~testclass1(void);

        template<class A> static bool foo(int i)
        {
            std::cout <<"in static foo";    
            return true;
        }
    };


namespace test2
{
    class testclass2
    {
    public:
        testclass2(void);
        ~testclass2(void);
    };

    bool b = testclass1::foo<int>(2);
}

EDIT:

A few people mentioned that I need to call this inside the function and this will work without any problem.
I understand that; the only reason I asked this question is because I saw this code somewhere (in someone’s elses project) and was wondering how and why this works. Since I never really seen anyone doing it before.

Also, this is used (in multiple places) as a way to call and instantiate a large number of classes like this via those function calls (that are outside). They get called first before anything else is instantiated.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T19:28:44+00:00Added an answer on May 12, 2026 at 7:28 pm

    C++ is not Python. You write statements in functions and execution starts from the main method. The reason bool b = ... happens to work is that it’s defining the global variable b and the function call is merely the initialization expression.

    Definitions can exist outside functions while other statements can only exist inside a function body.

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