Question

I have created a batch file to execute 10 commands at one time as follows but everytime I run it in command prompt. It leaves the last parameter as it is i.e., it ignores the 10th parameter

echo off
c:
“H[vzmwwdminta1sd]S[#]P[8080].exe” “C:\NDM_To_BatchDispatcher\NDM\INBOUND_FILES\%1”
| “H[vzmwwdminta1sd]S[#]P[8080].exe” “C:\NDM_To_BatchDispatcher\NDM\INBOUND_FILES\%2”
| “H[vzmwwdminta1sd]S[#]P[8080].exe” “C:\NDM_To_BatchDispatcher\NDM\INBOUND_FILES\%3”
| “H[vzmwwdminta1sd]S[#]P[8080].exe” “C:\NDM_To_BatchDispatcher\NDM\INBOUND_FILES\%4”
| “H[vzmwwdminta1sd]S[#]P[8080].exe” “C:\NDM_To_BatchDispatcher\NDM\INBOUND_FILES\%5”
| “H[vzmwwdminta1sd]S[#]P[8080].exe” “C:\NDM_To_BatchDispatcher\NDM\INBOUND_FILES\%6”
| “H[vzmwwdminta1sd]S[#]P[8080].exe” “C:\NDM_To_BatchDispatcher\NDM\INBOUND_FILES\%7”
| “H[vzmwwdminta1sd]S[#]P[8080].exe” “C:\NDM_To_BatchDispatcher\NDM\INBOUND_FILES\%8”
| “H[vzmwwdminta1sd]S[#]P[8080].exe” “C:\NDM_To_BatchDispatcher\NDM\INBOUND_FILES\%9”
| SHIFT
| “H[vzmwwdminta1sd]S[#]P[8080].exe” “C:\NDM_To_BatchDispatcher\NDM\INBOUND_FILES\%9”

Any suggestions??

Thanks
Priyanka

Answer 1

You can try doing this in a for loop:

for /l %%i in (1,1,10) do (
    "H[vzmwwdminta1sd]S[#]P[8080].exe" "C:\NDM_To_BatchDispatcher\NDM\INBOUND_FILES\%1"
    SHIFT
)

EDIT: shift doesn’t work in a for loop because all the lines within the parens are interpreted at the same time, for all iterations, but you can roll your own loop:

@echo off
set i=1
:loop
if %i% GEQ 11 goto :end
"H[vzmwwdminta1sd]S[#]P[8080].exe" "C:\NDM_To_BatchDispatcher\NDM\INBOUND_FILES\%1"
SHIFT
set /a i+=1
goto :loop

:end
@echo All done.

Another solution would be to use a for loop but call a sub-procedure to do the shift.