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Home/ Questions/Q 9258757
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T12:29:18+00:00 2026-06-18T12:29:18+00:00

I have created a dice function that trows random dices and sum the value

  • 0

I have created a dice function that trows random dices and sum the value of them.

Now every number from 0-9 is connected to a class, so if i get number 4 it should call class ” four”
So i created a switch from 0-9 .
But when i get a sum more than 9 its give me the default number, since the function dosent know that 11 is actually 2 numbers.
I was wonder I its possible to split the numbers and put them into an array so when i pass it to the switch it gets med “one” “one” .

Any ideas ?

var value = total;
    switch(this.value){
        case 1:
            value ="one";
            break
        case 2:
            value ="two";
            break
        case 3:
            value ="three";
            break
        case 4:
            value ="four";
            break
        case 5:
            value ="five";
            break
        case 6:
            value ="six";
            break
        case 7:
            value ="seven";
            break
        case 8:
            value ="eight";
            break
        case 9:
            value ="nine";
            break
        case 0:
            value ="zero";
            break
        default:
            value ="zero" 
    }
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  1. Editorial Team
    Editorial Team
    2026-06-18T12:29:22+00:00Added an answer on June 18, 2026 at 12:29 pm

    You could use the string split function for that:

    var result = this.value.toString(10).split("").map(function(digit) {
        return ["zero", "one", "two", "three", "four", "five",
                "six", "seven", "eight", "nine"][digit];
    });
    

    (Of course you can use a loop instead of map; Check this answer and its comments on how the array thing works)

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