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Home/ Questions/Q 666839
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T23:51:46+00:00 2026-05-13T23:51:46+00:00

I have created a drop down with jQuery that can be seen here by

  • 0

I have created a drop down with jQuery that can be seen here by clicking the Preview button on top:

var open_submenu = null;

$(function(){
  $('.dropdown').hover(function(){

    // hide all previous submenus and fix queue buildup problem
    $('.sublinks').stop(false, true).hide();

    // get corresponding submenus
    var submenu = $(this).parent().next();

    $(this).parent().nextAll().stop();

    $(submenu).css({
      top: $(this).offset().top + $(this).height() + 4 + 'px',
      left: $(this).offset().left + 'px',
      zIndex:10000
    });

    // show the submenu
    $(submenu).stop().slideDown(300);

    open_submenu = submenu;

    submenu.hover(function(){}, function(){
      $(this).slideUp(300);
    });
  }, function(){});
});

http://jsbin.com/ubire3/edit

It works fine except for one problem. When I hover over the main hover links (blue ones) quickly eg. going horizontally quickly hovering each top menu, the some submenus don’t close. How do I make it so that even if I hover fast over them all other submenus are closed?

Edit

I saw this useful link using some ways to avoid this, but having bit of problems, how to apply that in my case.

What are queues in jQuery?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T23:51:47+00:00Added an answer on May 13, 2026 at 11:51 pm

    Great, finally I solved the problem myself:

    All I did was to modify the line:

    $('.sublinks').hide();
    

    to

    $('.sublinks').stop(false, true).hide();
    

    The stop stopped animations for previous sub-menus. You can see the documentation of it on the jQuery site.

    See fixed version here:

    http://jsbin.com/ubire3/5/edit

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