Question

I have created a function to count the duplicate items in array .
And everything is fine . but I want to output the unique items only , and this is my problem .

My function:

void RepeatedCounter(int n){
    int i, j, temp, count= 0;
    int *Numbers = new int[n];
    for(i=0;i<n;i++){
        cout << "Enter the number (" << i+1 << "): "; 
        cin >> *(Numbers+i);
    }
    cout << "---------------------\n";
    for(i=0;i<n;i++){
        temp = *(Numbers+i);
        for(j=0;j<n;j++){
            if(temp == *(Numbers+j)){
                ++count;
            }
        }
        if(*(Numbers+i+1) != temp)
        cout << *(Numbers+i) << "= " << count << endl;
        count= 0;
    }

    delete []Numbers;
}

Main function:

int Num_Of_Digits= 0;
cout << "How many numbers: ";
cin >> Num_Of_Digits;
RepeatedCounter(Num_Of_Digits);

Example:

Inputs  
1  
5  
3  
5  
1  

Wrong result (current output)

1= 2   
5= 2  
3= 1  
5= 2   
1= 2  

What I want

1= 2     
5= 2  
3= 1  

Answer 1

Try this,

for(i=0;i<n;i++){
    count= 0;
    temp = *(Numbers+i);
    bool found = false;
    for(j=0;j<n;j++){
        if(temp == *(Numbers+j)){
            ++count;
        }
    }
    for(j=i+1;j<n;j++) {
        if(temp == *(Numbers+j)){
            found = true;
        }
    }
    if(found) continue;
    if(*(Numbers+i+1) != temp)
    cout << *(Numbers+i) << "= " << count << endl;
}