Question

I have created a label with overriding its paintComponent (to paint it in a different format with an arc) and located them on a panel. Everything worked fine, however the labels which are located in same location (by .setlocation) are creating problems.

Lets say I have 3 labels at the same location with different shapes. A-B-C
A is first created, then B is created and lastly c is created.
When I click on A, my function paints A and displays “youve clicked A”

But when I click on B or C, it acts like i have clicked on A.

(I’m adding labels in a panel stacked in scroll pane )

Here is the code where i make labels

for(int i=0;i<rowcount;i++){
        arcstart = Rawazimuth(azimuth[i]);
                    //custom JLabel to paint it like an arc
        MyLabel FLabel = new MyLabel(100, 50, (int)arcstart,cellid[i],lon[i],lat[i]);
        FLabel.setOpaque(true);
        Dimension LabelSize = new Dimension( 100,50);
        FLabel.setSize(LabelSize);
                    //locate the JLabel to labels location. it might be same or not
        FLabel.setLocation(lon[i], lat[i]);

        MyPanel.add(FLabel);    
}

this is my custom jlabel class

public MyLabel(int W, int H, int start,int outcellid,int lonn, int latt) {
    addMouseListener(this);
    arcsizeW = W;
    arcsizeH = H;
    arcstart = start;
    cellid = outcellid;
    clicked = false;
    lon = lonn;
    lat = latt;
}

@Override
public void paintComponent(Graphics g){
    // true if button is clicked, so paint acordingly
    if(clicked ==true){
       g.setColor(dummyg.getColor());  
   }else{
       g.setColor(Color.blue);
   }
  // draw the arc
   g.fillArc(0, 0,arcsizeW , arcsizeH, arcstart, 60);
}

 //if cell is clicked, change its color to red and print its cellid
@Override
public void mouseClicked(MouseEvent e) {

    System.out.println(cellid);

     dummyg = this.getGraphics();
     dummyg.setColor(Color.red);
    this.paintComponent(dummyg);
    clicked = true;
}// other listener stuff}

so how do i prevent this?
i think i can use jlayerpane, but i will need at least 4 layers ( dunno if its ok ).

Answer 1

I have solved my problem.

The real problem that i found was, Java is interpreting each component with their x,y location and width & height. So even if your label does not overlap ( graphically ) they can be interpreted as same component.

To solve my problem,
I found the angle between mouse click point and component center; then calculated the closest component and reached it.

Layers and such doesn’t work in this situation, the only other way around is possibly overriding the contains method for the actualy shape.