Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 3992244
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 20, 20262026-05-20T06:44:29+00:00 2026-05-20T06:44:29+00:00

I have created a new AjaxLink in my .java file add(new AjaxLink(link){ private static

  • 0

I have created a new AjaxLink in my .java file

add(new AjaxLink("link"){                                                                                                                                                                                                                                                                                                  
private static final long serialVersionUID = 1L;                                                                                                       

@Override                                                                                                                                              
public void onClick(AjaxRequestTarget target) {                                                                                                        
target.appendJavascript("window.open('http://www.cnn.com/2011/WORLD/africa/02/23/libya.protests/index.html?hpt="+T1+"')");              
}                                                                                                                                                      
});

And added it to my .html file

<a href="#" wicket:id="link">TEXT TO REPLACE</a> 

The url is just an example but T1 is dynamic and I get that from my .java file. I would like the “TEXT TO REPLACE” to equal the T1 string but I don’t know how to do this. I have tried creating a Label and adding it like

<a href="#" wicket:id="link"><span wicket:id="linkLbl"></span></a> 

but that gives an error.

Any suggestions?

Thanks

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-20T06:44:29+00:00Added an answer on May 20, 2026 at 6:44 am

    The Label is the right direction, but you have to make sure that you add the label in the java code as well, it should be a child component of your ajax link.

    (On a sidenote: you might want to consider using <wicket:container> instead of <span>. In this case it doesn’t matter much, but there are cases where an extra <span> tag would make your HTML invalid.)

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

We have created a new List View Style that shows thumbnails from a picture
I have created a new solution with a minimal amount of code that represents
I m new to use ankhSVN and having issues. I have created some new
Does a new SessionFactor y and Session object have to be created for each
How to create new PCL file similar to existing MS doc. I have MS
Using TFS 2010. I have created a number of new Build Definitions. I also
I have created a new WCF service library type project. I have created a
I have created a new DesktopApplication in Netbeans. When I start it, it shows
I have created a new user account on my mac and I am trying
good morning, I have created a new content type - petition, a last step

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.