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Editorial Team
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Asked: 2026-06-13T13:10:55+00:00

I have created a reg expression to find all files in a directory whose

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I have created a reg expression to find all files in a directory whose file name starts with “installation” and has 6 numbers after that.

What I am looking to do is get a list of files name beginning with “installation” with only 6 numbers after it. For instance, right now I have six files (test files):

installation.php
installation000001.php
installation000002.php
installation000003-sweep.php
installation000004.php
installation-sweep.php

the expression that I am using with php is /^installation([0-9]{6})/ which pulls:

installation000001.php
installation000002.php
installation000003-sweep.php
installation000004.php

I only want to pull 1, 2 and 4 (not installation000003-sweep.php). Also, how can I start from 000002 that would only pull:

installation000002.php
installation000004.php

?

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1 Answer

  1. Editorial Team

    If you only want the ones with numbers then .php:

    /installation([0-9]{6}).php/

    Combine it with starting at 2 you can just do:

    /installation([0-9]{5}[2-9]).php/
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