Question

I have created a script in which a i have to create a image at runtime using a 64bitencoded string .i m using imagecreatefromstring function of PHP but it works in my Windows XAMPP based PHP , but not on my cloud side applications which i deployed on Amazon cloud running SUSE version of Linux.

Can u give me any suggestion to overcome the problem.
Or is there any other function which is capable to create the image from the encoded string passed to it.

Thanks in adv

I am using following code

<?php
         require ('../dbconfig/dbConfig.php');

    $gameId = $_POST["gameId"];
    $username = $_POST['email'];
    $imagedata =  $_POST['imagedata'];

    $uploaddir = './../blogdata/i/'; 

    $countSql =  mysql_query("select  max(_id) as fileName  from blog_data ");

    while($rowCommentData = mysql_fetch_assoc($countSql))
    {
        $num = $rowCommentData["fileName"];
        $file = ++$num.".png";
        $filedb = $uploaddir .$file;
    }


   /* $imagedata= 'iVBORw0KGgoAAAANSUhEUgAAABwAAAASCAMAAAB/2U7WAAAABl'
               . 'BMVEUAAAD///+l2Z/dAAAASUlEQVR4XqWQUQoAIAxC2/0vXZDr'
               . 'EX4IJTRkb7lobNUStXsB0jIXIAMSsQnWlsV+wULF4Avk9fLq2r'
               . '8a5HSE35Q3eO2XP1A1wQkZSgETvDtKdQAAAABJRU5ErkJggg==';*/

    $imagedata= base64_decode($imagedata);

    if(($img = @imagecreatefromstring($imagedata)) !== FALSE) 
    {

            if(imagepng($img,$filedb))
            {       
                    imagedestroy($img);

                    $sql="Insert into blog_data (game_id,text,type,username)".
                                   "Values('$gameId','$file','i','$username')";

                    $result=mysql_query($sql);

                    if($result == 1)
                    {
                        echo $file; 
                    }
                    else
                    {
                        echo "error2";
                    }
            } 
            else {
                echo "error1";
            }               
                   }
    else
    { 
         echo "error0";
    }

?>

By running PHP info there i got this information

Answer 1

The PHP needs to have the libgd extension installed and loaded. Check phpinfo() if it’s there. You probably can install it via yum. The package should be called php5-gd