Question

I have created a UserControl that has a ListView in it. The ListView is publicly accessible though a property. When I put the UserControl in a form and try to design the ListView though the property, the ListView stays that way until I compile again and it reverts back to the default state.

How do I get my design changes to stick for the ListView?

Answer 1

You need to decorate the ListView property with the DesignerSerializationVisibility attribute, like so:

[DesignerSerializationVisibility(DesignerSerializationVisibility.Content)] public ListView MyListView { get { return this.listView1; } } 

This tells the designer’s code generator to output code for it.