Question

I have created a xml file from a dataset, but the first node is <NewDataset> i need to change that to <FormData> and i also need to add in some parameter like Platform=”Android” and Version=”488″.

Is there any way to change it while it is still a dataset or will i have to call up the file after i change it and then save it?

My knowledge of data files is minimal and i really need some help.

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Current xml file

<NewDataSet>
  <FieldData>
    <property_details_gps_location>-29.77861, 31.008617</property_details_gps_location>
    <property_details_address_address1>27 MANJEE</property_details_address_address1>
    <property_details_address_address2>KENVILLE</property_details_address_address2>
    <property_details_address_city>ETHEKWINI</property_details_address_city>
    <property_details_address_state>KWAZULU NATAL</property_details_address_state>
  </FieldData>
</NewDataSet>

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What i hope to achive:

<FormData Platform="Android" PlatformVersion="73" Version="488" DataVersion="1" Description="Investec - Res" FormId="d617a5e8-b49b-4640-9734-bc7a2bf05691" FileId="bce3a788-6725-4ce2-b965-1b55c6e7cc95" EncryptionVerification="" CreatedBy="Shaunm" EditedBy="Shaunm">
  <FieldData>
    <property_details_gps_location>-29.77861, 31.008617</property_details_gps_location>
    <property_details_address_address1>27 MANJEE</property_details_address_address1>
    <property_details_address_address2>KENVILLE</property_details_address_address2>
    <property_details_address_city>ETHEKWINI</property_details_address_city>
    <property_details_address_state>KWAZULU NATAL</property_details_address_state>
  </FieldData>
</FormData>

Answer 1

You can easily modify/add elements/attributes via LINQ to XML.

 XDocument doc = XDocument.Parse(dataSetObject.GetXml());
 doc.Root.Name  = "FormData ";
 doc.Root.Add(new XAttribute("Platform", "Android"));
 ...
 doc.Save("sample.xml");

To list the child nodes,

foreach (XElement element in doc.Root.Element("FieldData").Descendants())
 {
   Console.WriteLine(element.Name + " : " + element.Value );
  }