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Home/ Questions/Q 9165867
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T15:00:39+00:00 2026-06-17T15:00:39+00:00

I have created plugin which do particular things with data, now I would like

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I have created plugin which do particular things with data, now I would like somehow join my plugin to use if with ex. jQuery dialog. How can I do this?

this is simplified situation:

(function($) {
    $.fn.jquerytoc = function(map, layersConfig, layersList) {

        var opts = $.extend($.treeview, $.fn.jquerytoc.defaults, map, layersConfig, layersList);

        var TOC = {
            map : opts.map,
            layersConfig : opts.layersConfig,
            TOCinfos : {},
            getRequiredData : function() {

            },
            init : function() {
                this.getRequiredData();
            }
        };
        var HTML = {
            nodes : TOC.TOCinfos,
            data : [],
            htmlObject : {},
            jqTreeObject : {},
            setHTMLcode : function() {
                var object = this.data;
                var objectNode = {};

                var nodes = this.nodes;
                console.log(nodes);
                for (var node in nodes) {
                    objectNode = {};

                    objectNode.label = nodes[node].name;
                    objectNode.children = [];

                    var sublayers = nodes[node].sublayers;
                    for (var sublayer in sublayers) {
                        objectNode.children.push({
                            'label' : sublayers[sublayer]
                        });
                    };
                    object.push(objectNode);
                };
            },
            init : function(object) {
                this.htmlObject = object;
                this.setHTMLcode();
            }
        };
        function init() {
            TOC.init();
            HTML.init(this);
        }
        return this.each(function() {
            init();

//AND HERE I WOULD LIKE TO WRAP MY DOM ELEMENT WITH JQUERY DIALOG
jQuery.dialog(this);
        });
    }
})(jQuery);

but I always get that jQuery method dialog is undefined. I tried it in many ways but always get same error. I would be glad for help! thanks! 🙂

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T15:00:40+00:00Added an answer on June 17, 2026 at 3:00 pm

    Use jQuery(this).dialog() instead of jQuery.dialog(this)

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