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Editorial Team
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Asked: 2026-05-24T16:04:09+00:00

I have created the following function to check the first value of the check

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I have created the following function to check the first value of the check box when loading a page – 

function defaultCheck(){
      document.checkBoxForm.list[0].checked = true;
      var val=document.checkBoxForm.list[0].value;
      showtotal[0] = document.checkBoxForm.list[0].value;
      show(val);
      editVal();
      //alert('ajhsdjha');
 }

I have used the function in html page load by <body onload="defaultCheck()">.

My problem is – when there are more than one values in the list the function by default selects the first one but when there is just one value in the list, it does not select it. The values of check boxes are dynamically retrieved from database by – 

 <?php
     while($row=mysql_fetch_array($levelq)) {?>
        <input type='checkbox' name="list" value="<?=$row['tag']?>"  
               id="<?=$row['tag']?>" onclick="" />
        <?  echo $row['tag'].' '.'<br/><br/>'; 
     }
?>

I have no idea why is it behaving so weird. Can anyone help me out please?

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1 Answer

  1. Editorial Team

    Like @cwallenpoole said, you should be doing this in PHP.

    If you still want to do it in JS, here you go:

    function defaultCheck(){
      if(document.checkBoxForm.list.length > 1) {
          document.checkBoxForm.list[0].checked = true;
          var val=document.checkBoxForm.list[0].value;
          showtotal[0] = document.checkBoxForm.list[0].value;
      } else {
          document.checkBoxForm.list.checked=true;
          var val=document.checkBoxForm.list.value;
           showtotal[0] = document.checkBoxForm.list.value;
      }
      show(val);
      editVal();
      //alert('ajhsdjha');
 }

    This happens because, when there is only 1 checkbox, list refers to that checkbox, NOT the array of checkboxes

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