Question

I have created this php script which displays the contents of a designated directory and allows users to download each file. Here is the code:

<?php  
if ($handle = opendir('test')) {  
     while (false !== ($file = readdir($handle))) {  
        if ($file != "." && $file != "..") {  
            echo "<a href='test/$file'>$file\n</a><br/>";  
        }  
    }  
    closedir($handle);  
}
?>

This script also displays folders, but when I click a folder, it does display the contents of the folder, but in the default Apache autoindex view.

What I would like the script to do when a folder is clicked, is display the contents, but in the same fashion as the original script does (as this is more editable with css and the like).
Would you know how to achieve this?

Answer 1

Don’t create a link to the directory itself, but to a php page which displays the contents.

Change your php code to somthing like:

if(isset($_REQUEST['dir'])) {
    $current_dir = $_REQUEST['dir'];
} else {
    $current_dir = 'test';
}

if ($handle = opendir($current_dir)) {
     while (false !== ($file_or_dir = readdir($handle))) {
        if(in_array($file_or_dir, array('.', '..'))) continue;
        $path = $current_dir.'/'.$file_or_dir;
        if(is_file($path)) {
            echo '<a href="/Implementation/'.$path.'">'.$file_or_dir."\n</a><br/>";
        } else {
            echo '<a href="script.php?dir='.$path.'">'.$file_or_dir."\n</a><br/>";
        }
    }
    closedir($handle);
}

PS write you html code with double quotes.