Question

I have data in stl containers (vector). Each node in the vector is a structure which also contains stl strings.

struct record
{
string name;
string location;
int salary;
}

vector< record > employees;

I want to serialize employees but I also want to encrypt it before serializing.

my encryption function looks like this:

Encode(const char * inBfr, const int in_size, char ** outBfr, int& out_size )

By searching it looks like the stl standard doesn’t require the memory of my structure to be contiguous so I can’t just grab the memory of employees variable. Is there any other smart way that I can use this encoding function with my stl based structures/container? It is good for me that Encode function works in plain char * buffers so I know exactly what goes in and out but stl structures are not and I am tring to find a nice way so I can use stl with this function.

I am also opening to using any other stl containers if that helps.

Answer 1

Although the element in the std::vector<T> are guaranteed to be laid out contiguously, this doesn’t really help: the record you have may include padding and, more importantly, will store the std::string‘s content external to the std::string object (in case the small string optimization is used, the value may be embedded inside the std::string but it will also contain a couple of bytes which are not part of the std::strings value). Thus, you best option is to format your record and encrypt the formatted string.

The formatting is straight forward but personally I would encapsulate the encoding function into a simple std::streambuf so that the encryption can be done by a filtering stream buffer. Given the signature you gave, this could look something like this:

class encryptbuf
    : public std::streambuf {
    std::streambuf* d_sbuf;
    char            d_buffer[1024];
public:
    encryptbuf(std::streambuf* sbuf)
        : d_sbuf(sbuf) {
        this->setp(this->d_buffer, this->d_buffer + sizeof(this->d_buffer) - 1);
    }
    int overflow(int c) {
        if (c != std::char_traits<char>::eof()) {
            *this->pptr() = std::char_traits<char>::to_char_type(c);
            this->pbump(1);
        }
        return this->pubsync()? std::char_traits<char>::eof(): std::char_traits<char>::not_eof(c);
    }
    int sync() {
        char* out(0);
        int   size(0);
        Encode(this->pbase(), this->pptr() - this->pbase(), &out, size);
        this->d_sbuf->sputn(out, size);
        delete[] out; // dunno: it seems the output buffer is allocated but how?
        this->setp(this->pbase(), this->epptr());
        return this->d_sbuf->pubsync();
    }
};

int main() {
    encryptbuf    sbuf(std::cout.rdbuf());
    std::ostream eout(&sbuf);
    eout << "print something encoded to standard output\n" << std::flush;
}

Now, creating an output operator for your records just printing to an std::ostream can be used to create an encoded