Question

I have decided to use Exceptions in my code to pass error handling around. I found myself duplicating code each time I wanted to create a new exception. These classes were nothing special and only contained a messaged. But I have come to rely on type safety when handing them. Is there a way to provide a new exception class type without having to re-implement the constructors?

[Serializable]
class MyNewException : MyBaseException
{
    public MyNewException (String tMsg)
        : base(tMsg)
    {
    }

    public MyNewException (String tMsg, Exception tInnerEx)
        : base(tMsg, tInnerEx)
    {
    }
}

The code above is duplicated many times over for each different type of exception I want to define.

Answer 1

Unfortunately, no, the constructors have to be provided since they are not inherited.

In addition, unless you are catching these specific exceptions and performing explicit processing when they occur, I would recommend having a generic exception that contains the additional information that you might need. However, this may not apply in your case.