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Home/ Questions/Q 8196629
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T05:32:46+00:00 2026-06-07T05:32:46+00:00

I have declared: class aaa { public: static std::queue<QPair<void (*)( … ), int> >

  • 0

I have declared:

class aaa {
public:
    static std::queue<QPair<void (*)( ... ), int> > m_commands;
    static int bbb();
    static void ccc(...);
};

and in bbb() method I wrote:

int aaa::bbb() {
    m_commands.push( qMakePair( aaa::ccc, 0 ) );
}

but it complains about:

error C2664: 'void std::queue<_Ty>::push(QPair<T1,T2> &&)' : cannot convert parameter 1 from 'QPair<T1,T2>' to 'QPair<T1,T2> &&'

why? When I had function like that:

void reg( void ( *invoker )( ... ), int args  ) {
    m_commands.push( qMakePair( invoker, args ) );
}

I could easily send to the above function a static function this way:

reg( aaa::ccc, 0 );
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  1. Editorial Team
    Editorial Team
    2026-06-07T05:32:48+00:00Added an answer on June 7, 2026 at 5:32 am

    qMakePair( aaa::ccc, 0 ) is (presumably) returning a value of type QPair<void (*)(), int>, since it doesn’t know that you want a value of type QPair<void (*)( ... ), int>. Invoke it explicitly as qMakePair<void (*)( ... ), int>( aaa::ccc, 0 ) or reinterpret_cast aaa::ccc to the desired function pointer type.

    Not to mention that this is (almost certainly) illegal, as aaa::ccc does not have the correct signature and cannot be invoked through the function pointer type you’re using.

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