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Home/ Questions/Q 4341632
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T11:30:40+00:00 2026-05-21T11:30:40+00:00

I have defined a custom user type that works fine when used properties of

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I have defined a custom user type that works fine when used properties of my entities. For instance:

 <class name="com.my.sample" table="MY_TABLE">
    ...
    <property name="foo" type="myCustomUserType">
 </class>

I’m needing something like this:

 <class name="com.my.sample" table="MY_OTHER">
    ...
    <component name="myAddress" class="com.my.sample.Address">
       <property name="street" column="MY_OTHER_ADRR_STREET" />
       <property name="foo" type="myCustomUserType" column="MY_OTHER_ADRR_COLUMN" />
    </component>
 </class>

Obviously, I’m supposing that myCustomUserType is properly defined in the .HBM file. Is it possible to map a <component> property like this?

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  1. Editorial Team
    Editorial Team
    2026-05-21T11:30:40+00:00Added an answer on May 21, 2026 at 11:30 am

    Actually, it works fine. It is also possible to map <component> properties using relationships such as <many-to-one>. The mapping was somethig like this:

    <component name="myAddress" class="com.my.sample.Address" >
        <property name="aSimpleDate" column="TBL_ADDR_SIMPLE_DATE" type="date" />
        <many-to-one class="OtherClass" name="otherClass" >
            <column name="TBL_ADDR_OTHER_CLASS_ID" precision="9" scale="0"/>
        </many-to-one>
        <property name="foo" column="TLB_ADDR_FOO" type="myCustomUserType" />
    </component>
    

    Unfortunatelly, the Hibernate documentation is not very obvious about this.

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