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Home/ Questions/Q 6059819
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T08:45:17+00:00 2026-05-23T08:45:17+00:00

I have defined a enum as below in the XSD file <xs:simpleType name=PaperSizes> <xs:restriction

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I have defined a enum as below in the XSD file

 <xs:simpleType name="PaperSizes">
    <xs:restriction base="xs:string">
      <xs:enumeration value="NUMBERS"></xs:enumeration>
      <xs:enumeration value="PICTURE"></xs:enumeration>
      <xs:enumeration value="RTF"></xs:enumeration>
    </xs:restriction>

I need to override the detault values assigned by the compiler. ie:- for NUMBERS the default value will be 0. I need the value 2 for it.

What changes i need to make?

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-23T08:45:18+00:00Added an answer on May 23, 2026 at 8:45 am

    You cannot set a different default for each of the values in a collection. You can set one default value for any xsd simple type with the “default” keyword.

    So if you want to set a default value in your example above you could do something like:

    <xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema">
      <xs:element name="root">
        <xs:complexType>
          <xs:sequence>
            <xs:element default="PICTURE" name="PaperSizes">
              <xs:simpleType>
                <xs:restriction base="xs:string">
                  <xs:enumeration value="NUMBERS" />
                  <xs:enumeration value="PICTURE" />
                  <xs:enumeration value="RTF" />
                </xs:restriction>
              </xs:simpleType>
            </xs:element>
          </xs:sequence>
        </xs:complexType>
      </xs:element>
    </xs:schema>
    

    I hope this helps.

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