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Home/ Questions/Q 1106863
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T01:51:17+00:00 2026-05-17T01:51:17+00:00

I have defined a record which has lots of fields with different types (integer,

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I have defined a record which has lots of fields with different types (integer, real , string, … plus dynamic arrays in terms of “array of …”).
I want to save it as a whole to a file and then be able to load it back to my program. I don’t want to go through saving each field’s value individually.
The file type (binary or ascii or …) is not important as long Delphi could read it back to a record.

Do you have any suggestions?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T01:51:17+00:00Added an answer on May 17, 2026 at 1:51 am

    You can load and save the memory of a record directly to and from a stream, as long as you don’t use dynamic arrays. So if you use strings, you need to make them fixed:

    type TTestRecord = record 
      FMyString : string[20]; 
    end; 
    
    var 
      rTestRecord: TTestRecord;
      strm : TMemoryStream; 
    
    strm.Write(rTestRecord, Sizeof(TTestRecord) );
    

    You can even load or save an array of record at once!

    type TRecordArray = array of TTestRecord;
    
    var ra : TRecordArray; 
    
    strm.Write(ra[0], SizeOf(TTestRecord) * Length(ra));
    

    In case you want to write dynamic content:

    iCount   := Length(aArray);
    strm.Write(iCount, Sizeof(iCount) );      //first write our length
    strm.Write(aArray[0], SizeOf * iCount);   //then write content
    

    After that, you can read it back:

    strm.Read(iCount, Sizeof(iCount) );       //first read the length
    SetLength(aArray, iCount);                //then alloc mem
    strm.Read(aArray[0], SizeOf * iCount);    //then read content
    
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