Question

I have developed a Spring MVC – Hibernate application as told here.

Now I am trying to modify this code to create a REST application as told here.

I have added Jackson library to the classpath and added @XmlRootElement.

@XmlRootElement(name = "persons")
public class Person implements Serializable {

But if I do a application/json request then I still get the html code back.

What I am doing wrong / forgot to do?

My controller:

    @RequestMapping(value = "/persons", method = RequestMethod.GET)
    @ResponseBody
    public String getPersons(Model model) {

        logger.info("Received request to show all persons");

        // Retrieve all persons by delegating the call to PersonService
        List<Person> persons = personService.getAll();
        model.addAttribute("persons", persons);

        return "personspage";
    }

Changed the Controller, but get an error:
t

ype Status report

message /Buddies/WEB-INF/jsp/main/persons/1.jsp

description The requested resource (/Buddies/WEB-INF/jsp/main/persons/1.jsp) is not available.

Answer 1

Your controller should look like this:

@RequestMapping(value = "/persons/{id}", method = RequestMethod.GET)
@ResponseBody
public Person getPerson(@PathVariable int id) {
    Person person = personService.getPersonById(id);
    return person;
}

If you want to return a list of Person objects, you need an extra wrapper object, see: Using JAXB to unmarshal/marshal a List<String>.