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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T00:43:54+00:00 2026-05-23T00:43:54+00:00

I have developed an android application .In that application getting information from web and

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I have developed an android application .In that application getting information from web and displayed in the screen.At the time of getting information i want to load a progress dialog to the screen after getting the information i want dismiss the dialog

Please any one help me how to do this with some sample code

Thanks in advance

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  1. Editorial Team
    Editorial Team
    2026-05-23T00:43:55+00:00Added an answer on May 23, 2026 at 12:43 am

    You need to implement an AsyncTask.
    Example:

    class YourAsyncTask extends AsyncTask<Void, Void, Void> {
    
        private ProgressDialog progressDialog;
    
        @Override
        protected void onPreExecute() {
            //show your dialog here
            progressDialog = ProgressDialog.show(this, "title", "message", true, false)
        }
    
        @Override
        protected Void doInBackground(Void... params) {        
            //make your request here - it will run in a different thread
            return null;
        }
    
        @Override
        protected void onPostExecute(Void result) {
            //hide your dialog here
            progressDialog.dismiss();
        }
    }
    

    Then you just have to call

    new YourAsyncTask().execute();
    

    You can read more about AsyncTask here: http://developer.android.com/reference/android/os/AsyncTask.html

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