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Home/ Questions/Q 6634075
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T22:53:15+00:00 2026-05-25T22:53:15+00:00

I have directory structure like following: analytics / / \ \ conf script src

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I have directory structure like following:

           analytics  
       /   /     \   \
    conf script  src  other  
    /  \  /  \   /  \   
   <setup>         <source>  

< setup >:  
       setup.yaml  
       sql.yaml  

< source  >:  
       src/  
           folder A/  
                    s1.py  
                    s2.py  
                    ...  
           folder B/
                    m1.py  
                    m2.py  
                    ...  

How can I inclue the setup files in of this structure to the source files in structure without hardcoding the paths

I tried sys.path.append(‘< path >’) but when I try to open the file I see error

>>> import sys
>>> sys.path.append('/Users/user/Documents/work/dw/analytics/conf')
>>> f = open('setup.yaml', 'r')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
IOError: [Errno 2] No such file or directory: 'setup.yaml'
>>> f = open('setup.yaml', 'r')
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  1. Editorial Team
    Editorial Team
    2026-05-25T22:53:16+00:00Added an answer on May 25, 2026 at 10:53 pm

    open() (and all the other file access functions) don’t care about sys.path. It’s only used when importing modules.

    Create your own variable that contains the path that contains your files, and use it.

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