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Editorial Team
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Asked: 2026-06-09T19:30:56+00:00

I have document grandchild.xml whose result after being processed with granchild.xsl must be forwarded

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I have document grandchild.xml whose result after being processed with granchild.xsl must be forwarded to child.xsl, then it must be finally processed and output by parent.xsl.

I have tried adding an xml-stylesheet element to the result document, expecting it to processed using by the referenced XSL stylesheet, but nothing happened.

What is the correct declaration to accomplish this task? I have searched a lot on Internet, with no results.

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1 Answer

  1. Editorial Team

    Unless anybody knows any better, I believe the ability to recursively process XSLT output on a browser is impossible.

    To prove it, I have just tried the following in IE8, FF14 and Chrome…

    level1.xml

    <?xml version="1.0" encoding="utf-8" ?> 
<?xml-stylesheet title="XSL_formatting" type="text/xsl" href="level1.xsl"?>
<data>
  <id>Level 1 data</id>
</data>

    level1.xsl

    <?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
   <xsl:template match="/">
     <?xml-stylesheet title="XSL_formatting" type="text/xsl" href="level2.xsl"?>
     <data2>
       <id2>Level 2: <xsl:value-of select="/data/id"/></id2>
     </data2>
   </xsl:template>   
</xsl:stylesheet>

    level2.xsl

    <?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
   <xsl:template match="/">
     <html>
       <body>
         <b>Level 3:</b> <xsl:value-of select="/data2/id2"/>
       </body>
     </html>
   </xsl:template>   
</xsl:stylesheet>

    The result from all 3 browsers is simply to display Level 2: Level 1 Data.

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