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Home/ Questions/Q 6175201
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T23:53:02+00:00 2026-05-23T23:53:02+00:00

I have done a little research on the following error Warning: [json] (php_json_encode) type

  • 0

I have done a little research on the following error Warning: [json] (php_json_encode) type is unsupported, encoded as nullbut have not found much in the way of answers?

I am trying to encode the result of a mysql query. Not sure what info I can provide.. but when I echo the results of the mysql data using

$data = json_encode($result);

echo $data;

while($info = mysql_fetch_array($result))
            {
            $content[] = $info;
            }

$count = count($content);

    for($i=0;$i<$count;$i++){

        echo $content[$i]['Name'];

    }

every thing shows as normal. Any help would be great.

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  1. Editorial Team
    Editorial Team
    2026-05-23T23:53:03+00:00Added an answer on May 23, 2026 at 11:53 pm

    What about:

    $result=array();
    for($i=0;$i<$count;$i++)
    {
        $result[]=$content[$i]['Name'];
    }
    echo json_encode($result);
    
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