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Home/ Questions/Q 3491522
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T11:38:49+00:00 2026-05-18T11:38:49+00:00

I have done this many times before, to re-use a value passed into the

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I have done this many times before, to re-use a value passed into the sprintf() function. But this code is returning a “Warning: sprintf() [function.sprintf]: Too few arguments in…” message.

Here is the code:

$search_clause = sprintf(" (msgBody LIKE %%%1$s%% OR msgSubject LIKE '%%%1$s%%' ) ", mysql_real_escape_string($match1));

Ideally the value of $match1 will be inserted into the segment of the SQL WHERE clause shown above – twice, each wrapped by ‘%’ characters for a wildcard search.

If $match1 = “test”, the resulting string value of $search_clause would be:

(msgBody LIKE '%test' OR msgSubject LIKE '%test%' )

What is the obvious mistake I’m making??

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  1. Editorial Team
    Editorial Team
    2026-05-18T11:38:49+00:00Added an answer on May 18, 2026 at 11:38 am

    The $s is probably getting interpreted as a variable (see variable expansion). Try using single quotes instead:

    $search_clause = sprintf(' (msgBody LIKE "%%%1$s%%" OR msgSubject LIKE "%%%1$s%%" ) ', mysql_real_escape_string($match1));
    
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