Question

I have done this several times before but for some reason I can’t get the post to go through… I tried the php script with the variables set to _POST and without… When they aren’t set to post it works fine. Here is my iOS code:

NSDate *workingTill = timePicker.date;
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:@"HH:mm"];
NSString *time = [formatter stringFromDate:workingTill];

NSString *post = [NSString stringWithFormat:@"shift=%@&username=%@", time, usernameString];

NSData *postData = [post dataUsingEncoding:NSUTF8StringEncoding allowLossyConversion:NO];
NSString *postLength = [NSString stringWithFormat:@"%d", [post length]];

NSURL *url = [NSURL URLWithString:@"http://wowow.php"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0];
[request setHTTPMethod:@"POST"];
NSLog(@"%@", post);
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setHTTPBody:postData];

[NSURLConnection connectionWithRequest:request delegate:nil];

[self.navigationController popToRootViewControllerAnimated:YES];

And here is a chunk of the php, are the POST variables not in the right location?

<?php
function objectsIntoArray($arrObjData, $arrSkipIndices = array())
{
    $arrData = array();

    // if input is object, convert into array
    if (is_object($arrObjData)) {
        $arrObjData = get_object_vars($arrObjData);
    }

    if (is_array($arrObjData)) {
        foreach ($arrObjData as $index => $value) {
            if (is_object($value) || is_array($value)) {
                $value = objectsIntoArray($value, $arrSkipIndices); // recursive call
            }
            if (in_array($index, $arrSkipIndices)) {
                continue;
            }
            $arrData[$index] = $value;
        }
    }
    return $arrData;
}

    $newShift = $_POST('shift');
    $bartenderUsername = $_POST('username');

    mysql_connect("host", "name", "pw") or die(mysql_error());  
    mysql_select_db("harring4") or die(mysql_error());

    $result = mysql_query("SELECT * FROM BartenderTable WHERE username='".$bartenderUsername."'") or die(mysql_error());  

    $row = mysql_fetch_array($result);
    $newfname = $row['fname'];

I imagine this is a rather simple answer to a more experience developer, thanks for your help!

Answer 1

$_POST is an array, not a function. You need square brackets to access array indices:

$newShift = $_POST['shift'];
$bartenderUsername = $_POST['username'];