Question

I have done up a program which requires the following:

1. prompts user input account no
2. prompts user input account type
   2. if account type == a, prompts some input and does a certain formula [if]
   3. if account type == b, prompts some input and does another formula [else if]
   4. if account type is wrong(not a or b), prompts error and return to 2 [else]
3. prompts user input to exit [do while]
   3. if input == y, exits
   4. if input == n, return to 1

at the moment I’m pretty stuck at 2.3.
it prompts the error and goes to 3 instead of returning to 2 to prompt user input.

where is the problem? the else?

Answer 1

You have to use a loop to keep asking for an account type if the type is wrong:

do
{
    //1
    do 
    {
        //2
        if (type =="a")
            //2.1
        else if(type=="b")
            //2.2
        else
            //2.3
    } 
    while (type != "a" and type != "b");
    //3
    if(input == "y")
        return;
}
while (input == "n");