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Home/ Questions/Q 6248121
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T12:59:54+00:00 2026-05-24T12:59:54+00:00

I have elements like user[0][foo], user[0][bar], user[1][foo], user[2][bar] which are names of select tags.

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I have elements like

user[0][foo], user[0][bar], user[1][foo], user[2][bar]

which are names of select tags.

I want use the ^= operator to use jQuery('select[name^=(something)')
so that I can gather all the foos together.

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  1. Editorial Team
    Editorial Team
    2026-05-24T12:59:55+00:00Added an answer on May 24, 2026 at 12:59 pm

    Is there anything stopping you using the ends with selector instead?

    jQuery('select[name$="foo\\]"]');
    

    Note we’re having to escape the “]” as it’s a “meta-characters”:

    If you wish to use any of the meta-characters ( such as !”#$%&'()*+,./:;<=>?@[]^`{|}~ ) as a literal part of a name, you must escape the character with two backslashes: \\. For example, if you have an element with id=”foo.bar”, you can use the selector $(“#foo\\.bar”)

    http://api.jquery.com/category/selectors

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