Question

I have few text files that has some key words. I have to select few lines from those files and parse it. Below is a sample file. I have to grep for “Customer” and get the line from the file.

13 Sun Sep  9 12:14:38 2012 : [P] Reproducer has the 167 number 
13 Sun Sep  9 12:14:38 2012 : [P] Customer has the 12.14.19.9 
13 Sun Sep  9 12:14:38 2012 : [P] Customer has the 12.14.89.9 
13 Sun Sep  9 12:14:38 2012 : [P] Reproducer has the 170 number 
13 Sun Sep  9 12:14:38 2012 : [P] Customer has the 12.4.89.16 

I have to select only the lines that has Customer and have to parse it to get only the Timestamp (12:14:38) and the Number 12.14.19.9. I have to do this for multiple files. All the file has the same structure of the log. I have done this using the oneliner like below

grep Customer Neigh.log | cut -d " " -f 5- | cut -d ":" -f 1-4 | cut -d " " -f 1,8

But I need to do this inside a shell script. How can I do this. Can anyone help?

Thanks

Answer 1

One way using GNU awk:

for i in *.txt; do awk '/Customer/ { print $5, $NF > FILENAME".out" }' "$i"; done

If you are using BSD awk:

for i in *.txt; do awk '/Customer/ { out=FILENAME".out"; print $5, $NF > out }' "$i"; done