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Home/ Questions/Q 6030907
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T05:06:25+00:00 2026-05-23T05:06:25+00:00

I have five links on a page which display different content on another part

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I have five links on a page which display different content on another part of the page when clicked. Each link has an ID and I have a simple click function on document ready to select the first link:

$(‘#link1’).click();

How can I have it click one of the five links at random on document ready, instead of #link1 specifically? And yes, I realize that a click function probably isn’t the ideal way to handle this.

Thanks in advance!

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  1. Editorial Team
    Editorial Team
    2026-05-23T05:06:26+00:00Added an answer on May 23, 2026 at 5:06 am

    The smoov jQuery way of doing things:

    jQuery.jQueryRandom = 0;
    jQuery.extend(jQuery.expr[":"], {
      random: function(a, i, m, r) {
         if (i == 0) {
             jQuery.jQueryRandom = Math.floor(Math.random() * r.length);
         };
         return i == jQuery.jQueryRandom;
     } });
    
    <script type="text/javascript">
     $().ready(function() {
         alert($("a:random").click());
     }); 
     </script>
    

    (I knew about custom selectors, but still shamelessly stolen from here)

    Slightly less smoov:

    $(function() {
       var links = $('a');
       var randomNum = Math.floor(Math.random()*links.length)  
       links.get(randomNumber).click();
    } 
    

    If you want links with an ID that start with link, you can always do:

       var links = $("a[id^='link']");
    

    And now it doesn’t matter whether you use numbers or whatever. Anything that has an ID that starts with link. (naturally, you could apply it to a particular css class too)

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