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Home/ Questions/Q 7021791
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T23:29:49+00:00 2026-05-27T23:29:49+00:00

I have follow html code: <form id=form1 name=form1 method=post action=> <label><input type=radio name=RadioGroup1 value=1

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I have follow html code:

<form id="form1" name="form1" method="post" action="">
   <label><input type="radio" name="RadioGroup1" value="1" id="RadioGroup1_0" />Radio1</label>
    <br>
    <label><input type="radio" name="RadioGroup1" value="2" id="RadioGroup1_1" />Radio2</label>
    <br>
    <label for="text">Text inlocuit</label><input type="text" name="text" id="text" />
</form>

and a jquery simple function:

<script>
$(document).ready(function() { 
    $("#RadioGroup1_0").click(function() {
        $("input#text").empty();
        $("input#text").val()=1;       
    });

    $("#RadioGroup1_1").click(function() {
        $("input#text").empty();
        $("input#text").val()=2;       
    });

});
</script>

And is not working.It’s obviously that I made something wrong.
I try with simple radio and binding ‘click’, ‘change’, ‘mousedown’.
jQuery version 1.7.1

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T23:29:49+00:00Added an answer on May 27, 2026 at 11:29 pm

    try this code,

    $(document).ready(function() {
        $("input[type='radio']").click(function() {
            $("#text").val($(this).index("input[type='radio']")+1);
        });
    });
    

    http://jsfiddle.net/C7sbs/


    you can use

    $("#text").val(this.value); 
    

    or

    $("#text").val($(this).index("input[type='radio']")+1);
    
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