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Home/ Questions/Q 9029471
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T07:15:21+00:00 2026-06-16T07:15:21+00:00

I have following code: class A : public QObject { Q_OBJECT public: A() :

  • 0

I have following code:

class A : public QObject
{
    Q_OBJECT
public:
    A() : QObject()
    {
         moveToThread(&t);
         t.start();
    }
    ~A()
    {
         t.quit();
         t.wait();
    }

    void doSomething()
    { 
         QMetaObject::invokeMethod(this,"doSomethingSlot");
    }
public slots:
    void doSomethingSlot()
    {
         //do something
         emit ready();
    }
signals:
    void ready();
private:
    QThread t;
}

The question why from doSomething it must be call via QMetaObject::invokeMethod. I know that there is something with connection type. Could some one explain what is under the hood?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T07:15:21+00:00Added an answer on June 16, 2026 at 7:15 am

    As you haven’t specified a Qt::ConnectionType, the method will be invoked as Qt::AutoConnection, which means that it will be invoked synchronously (like a normal function call) if the object’s thread affinity is to the current thread, and asynchronously otherwise. “Asynchronously” means that a QEvent is constructed and pushed onto the message queue, and will be processed when the event loop reaches it.

    The reason to use QMetaObject::invokeMethod if the recipient object might be in another thread is that attempting to call a slot directly on an object in another thread can lead to corruption or worse if it accesses or modifies non-thread-safe data.

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