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Home/ Questions/Q 7851735
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T19:15:13+00:00 2026-06-02T19:15:13+00:00

I have following code, class AA { public static void main(String[] args) { long

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I have following code,

class AA {

    public static void main(String[] args) {

        long ll = 100 ;

        AA1 a1 = new AA1() ;

        if(ll == 100) // Marked line
            long lls [] = a1.val(ll);

    }
}

class AA1 {

    public long [] val (long ll1) {
        long [] val = new long []{1 , 2, 3};
        return val ;
    }

}

which executes properly without the marked line. However, gives error “.class expected” with marked line. Can anybody help me what is the problem and how to solve this ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T19:15:14+00:00Added an answer on June 2, 2026 at 7:15 pm

    Basically this is a simplified version of your problem:

    if (condition)
        int x = 10;
    

    You can’t do that in Java. You can’t use a variable declaration as the single statement in an if body… presumably because the variable itself would be pointless; the only purpose would be for the side effect of the expression used for the assignment.

    If you really want the pointless declaration, use braces:

    if (condition) {
        int x = 10;
    }
    

    It’s still useless, but at least it will compile…

    EDIT: Responding to the comment, if you need to use the variable outside the if block, you need to declare it before the if block, and also make sure it’s initialized before you read the value. For example:

    // Note preferred style of declaration, not "long lls []"
    long[] lls = null; // Or some other "default" value
    if (ll == 100) {
        // I always put the braces in even when they're not necessary.
        lls = a1.val(ll);
    }
    // Now you can use lls
    

    Or:

    long[] lls;
    if (ll == 100) {
        lls = a1.val(ll);
    } else {
        // Take whatever action you need to here, so long as you initialize
        // lls
        lls = ...;
    }
    // Now you can use lls
    

    Or possibly use a conditional expression:

    long[] lls = ll == 100 ? a1.val(ll) : null;
    
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