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Asked: 2026-05-15T08:23:23+00:00

i have following code for inserting another page into div An XHTML 1.0 Strict

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i have following code for inserting another page into div

An XHTML 1.0 Strict standard template

</style>
<script type="text/javascript">
function ajaxFunction(id, url){
    var xmlHttp;
    try {// Firefox, Opera 8.0+, Safari
        xmlHttp = new XMLHttpRequest();     
    } catch (e) {// Internet Explorer
        try {
            xmlHttp = new ActiveXObject("Msxml2.XMLHTTP");
        } catch (e) {
            try {
                xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
            } catch (e) {
                alert("Your browser does not support AJAX!");
                return false;
            }
        }
    }

    xmlHttp.onreadystatechange = function(){
        if (xmlHttp.readyState == 4) {
            //Get the response from the server and extract the section that comes in the body section of the second html page avoid inserting the header part of the second page in your first page's element
            var respText = xmlHttp.responseText.split('<body>');
            elem.innerHTML = respText[0].split('</body>')[0];
        }
    }

    var elem = document.getElementById(id);
    if (!elem) {
        alert('The element with the passed ID doesn\'t exists in your page');
        return;
    }

    xmlHttp.open("GET", url, true);
    xmlHttp.send(null);
}

http://www.boxyourtvtrial.com/&#8217;);”/>

but its not working properly
i also put google in address but still its not working
whats wrong with the code….

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1 Answer

  1. Editorial Team

    XMLHTTPRequest is not allowed to make requests any domain other than the one the HTML page was served from.

    Here’s some info on getting around that restriction.

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