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Home/ Questions/Q 961371
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T01:20:00+00:00 2026-05-16T01:20:00+00:00

i have following code #include <iostream> using namespace std; int main(){ int i; char

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i have following code

#include <iostream>
using namespace std;
int main(){

    int i;
     char *p="this is a string";
     i=reinterpret_cast<int>(p);
     cout<<i<<"\n":



     return 0;
}

output is:
7648
please explain reinterpret_cast

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  1. Editorial Team
    Editorial Team
    2026-05-16T01:20:00+00:00Added an answer on May 16, 2026 at 1:20 am

    reinterpret_cast<> here will convert without checking the p pointer to an int but you can’t make any assumption what this int would represent. The only thing you can do, is convert this pointer back to what it was.

    On a more practical note, it is likely that your compiler will put the address p points to into the int value, but int size may not match a system pointer size, so you should probably use something like uintptr_t for that instead of int.

    You can use something like Boost lexical_cast<> which would try to convert a string-representation of an integer to the real integer value but I’m not sure that was your goal here.

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