Question

I have following code

#include <stdio.h>
#include<ctype.h>

typedef struct {
  int Type;
  int Type2;
}foo;

typedef struct {
  char cData[40];
}bar;

int main()
{
  bar b1;
  strcpy(b1.cData,"11");
  foo *f=(struct foo *)&b1;
  printf("Type is  %d \n",f->Type);
  return 0;
}

But i am not getting the value of type 1 in f’s pointer , instead i am getting size of that particuler struct.

Answer 1

When I run the code (after correcting for errors), it prints 12593. Which is 49*256 + 49 – in other words, “11” as an integer (ascii 1 being 49). So nothing wrong with the code as far as I can see (apart from the memory layout assumptions pointed out by Benoit), so we do need to know what you expected to happen

#include <stdio.h>
#include<ctype.h>

typedef struct {
  int Type;
  int Type2;
}foo;

typedef struct {
  char cData[40];
}bar;

int main()
{
  bar b1;
  foo *f=(foo *)&b1;
  strcpy(b1.cData,"11");
  printf("Type is  %d \n",f->Type);
  return 0;
}