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Home/ Questions/Q 8689513
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T23:39:57+00:00 2026-06-12T23:39:57+00:00

I have following code: $query = SELECT ads.*, trafficsource.name AS trafficsource, trafficsource.id AS trafficsourse_id,

  • 0

I have following code:

$query = "SELECT ads.*,
       trafficsource.name AS trafficsource,
       trafficsource.id AS trafficsourse_id,
       FROM ads
           JOIN trafficsource ON ads.trafficsourceId = trafficsource.id
        WHERE advertiserId = '$advertiser_id'";

        $mysqli = new mysqli();
        $mysqli->connect('localhost', 'root', '', 'adsbase');
        $result = $mysqli->query($query);
        while ($row = $result->fetch_assoc()) {
            echo "<h2>Traffic Sources: {$row['trafficsource']}</h2>";
        }

This code show results like:

Traffic Sources: Example1
Traffic Sources: Example2
Traffic Sources: Example2
Traffic Sources: Example1
Traffic Sources: Example2
Traffic Sources: Example1

What I want and can’t figure out is to show results like:

Traffic Sources: Example1, Example2

So without duplicates and also all in one line.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T23:39:58+00:00Added an answer on June 12, 2026 at 11:39 pm

    You nearly had it:

        $result = $mysqli->query($query);
        $trafficeSources = array();
        while ($row = $result->fetch_assoc()) {
            $trafficSources[] = $row['trafficsource'];
        }
    
        echo '<h2>Traffic Sources: ' . implode(', ', $trafficSources) . '</h2>';
    

    EDIT: Query using DISTINCT

    I’m assuming you only need the traffic source name, but feel free to add more columns back in if they’re required. Bear in mind though that the DISTINCT applies to a distinct combination of all rows returned, so it may be possible that you could end up with duplicate traffic sources if other selected columns differ.

    $query = "SELECT DISTINCT trafficsource.name AS trafficsource
              FROM ads
              JOIN trafficsource ON ads.trafficsourceId = trafficsource.id
              WHERE advertiserId = '$advertiser_id'";
    
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