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Home/ Questions/Q 7849605
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T18:34:42+00:00 2026-06-02T18:34:42+00:00

I have following code snippet in my application activity. If user is landing on

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I have following code snippet in my application activity.

If user is landing on activity for the first time then only thing that will happen is changing the boolean variable shouldSleep to true.

Thereafter, else part will be executed which contains generation of notification at every 60 seconds.

But the main problem is if I execute this code, the activity NEVER gets displayed as it keeps looping in else part and hence go on sleeping.

What I want is remaining application should run normally while every 60 seconds, else part of this method should be executed.
I guess it has got something to do with AsyncTask but I don’t have much idea about it.

Any idea how to do this? Thanks in advance for your help.

boolean shouldSleep=false;
private void ShowNotification() 
{
    //DO SOME TASK

    if (shouldSleep) 
    {
        Thread.sleep(60000);
        //DO SOME TASK
    } 

    else
   {
        shouldSleep = true;
   }

        /** Calling the method recursively so that it always runs. */
        ShowNotification();
}
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  1. Editorial Team
    Editorial Team
    2026-06-02T18:34:43+00:00Added an answer on June 2, 2026 at 6:34 pm

    Maybe you can use a Timer object :

    new Timer().schedule(new TimerTask() {
        @Override
        public void run() {
            //This code is run all 60seconds
            myBooleanVar = true;
            //If you want to operate UI modifications, you must run ui stuff on UiThread.
            Activity.this.runOnUiThread(new Runnable() {
                @Override
                public void run() {
                    Activity.this.changeUiStuff();
                }
            });
        }
    }, 60000);
    
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