Question

I have following code to perform some regular expression on the string

public class RegexForPresto {

public static void main(String[] args) {

    Pattern p = Pattern.compile("^M^M rawtostampedMsg^L 48^UT ");

    String candidateString = "^M^M rawtostampedMsg^L 48^UT 1338802566.906^EOH^name;

    Matcher matcher = p.matcher(candidateString);
    String tmp = matcher.replaceAll("");

    System.out.println(tmp);
    }

    }

Instead of just getting

^EOH^name

I get following output when I execute

^M^M rawtostampedMsg^L 48^UT 1338802566.906^EOH^name

Also is it possible to remove “^EOH^” from the string so as to get only “name” as the output. I don’t know how to remove the special character( “^”). Any help is appreciated.

Thanks in advance.

Answer 1

Though I have not tested the code, I think this should work for you:

public class RegexForPresto {

 public static void main(String[] args) {

    Pattern p = Pattern.compile(Pattern.quote("^M^M rawtostampedMsg^L 48^UT ")); // <-- This line is changed

    String candidateString = "^M^M rawtostampedMsg^L 48^UT 1338802566.906^EOH^name;

    Matcher matcher = p.matcher(candidateString);
    String tmp = matcher.replaceAll("");

    System.out.println(tmp);
}
}