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Home/ Questions/Q 9092587
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T22:52:39+00:00 2026-06-16T22:52:39+00:00

I have following function: char * strAlloc(string str) { char * chArr = new

  • 0

I have following function:

char * strAlloc(string str) {
    char * chArr = new char[str.size()];

    for (size_t i = 0; i < str.size(); i++) {
        chArr[i] = str[i];
    }

    return chArr;
}

if i do a break after char * chArr = new char[str.size()]; the debugger says following:

chArr   0x00c38cf8 "ÍÍÍÍÍÍÍÍÍÍÍÍÍÍÍýýýý««««««««þîþîþ"

and if i do a break after the for iteration i get this:

chArr   0x00c38cf8 "***************ýýýý««««««««þîþîþ"

so what i’m doing wrong?

edit:

size_t const gSize = 15; typedef char * 
TMaze [gSize]; 
Maze[0] = strAlloc ("***************");

in type TMaze i need the pointer of the char arrays tried also str.size()+1 ,
same behaviour

edit2:

char * strAlloc(string const & str) {
    char * chArr = new char[str.size()+1];

    strcpy(chArr, str.c_str());

    return chArr;
}

did it!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T22:52:40+00:00Added an answer on June 16, 2026 at 10:52 pm

    You’re not null terminating. Why not just use strcpy(chArr, str.c_str());?

    And you’ll need to add one to your allocation, too: char* chArr = new char[str.size() + 1];

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